Sampling and ML estimation

Using TruncExpFam

We recommend installing the stable, peer-reviewed version of TruncExpFam, available on CRAN:

install.packages("TruncExpFam")

After successful installation, the package can be loaded with

library(TruncExpFam)
#> Welcome to TruncExpFam 1.2.1.
#> Please read the documentation on ?TruncExpFam to learn more about the package.

Sampling from a truncated distribution

TruncExpFam comes equipped with functions to generate random samples from no less than 12 different probability distributions from the truncated exponential family. You can read more about them by running ?rtrunc on your R console.

As an example, we will sample 100 values from a chi-square distribution with 14 degrees of freedom:

x <- rtrunc(100, family = "chisq", df = 14)

Different ways to do the same thing

By default, however, rtrunc() doesn’t generate a truncated distribution. As a matter of fact, the code above will generate the exact same sample as if were drawn from stats::rchisq(), watch:

set.seed(3067)
x2 <- rtrunc(20, "chisq", df = 14)

set.seed(3067)
x3 <- rchisq(20, 14)

identical(x2, x3)
#> [1] FALSE

Oh, wait… Those objects are supposed to be identical! What happened? Let’s investigate:

x2
#>  [1] 16.531982 10.021074 12.480308 16.165519 11.083118 32.684427 16.661472
#>  [8] 18.085124 10.921481 11.150269 10.673091 12.012880  7.986689  7.500130
#> [15] 10.951995  6.725427 10.789780  5.616512 20.081876  8.138363
x3
#>  [1] 16.531982 10.021074 12.480308 16.165519 11.083118 32.684427 16.661472
#>  [8] 18.085124 10.921481 11.150269 10.673091 12.012880  7.986689  7.500130
#> [15] 10.951995  6.725427 10.789780  5.616512 20.081876  8.138363
str(x2)
#>  'trunc_chisq' num [1:20] 16.5 10 12.5 16.2 11.1 ...
#>  - attr(*, "parameters")=List of 1
#>   ..$ df: num 14
#>  - attr(*, "truncation_limits")=List of 2
#>   ..$ a: num 0
#>   ..$ b: num Inf
#>  - attr(*, "continuous")= logi TRUE
str(x3)
#>  num [1:20] 16.5 10 12.5 16.2 11.1 ...
class(x2)
#> [1] "trunc_chisq"
class(x3)
#> [1] "numeric"

OK, so you can tell that the generated numbers are the same, but x2 and x3 are not literally the same objects because the former has a different class. These trunc_* classes are actually very special, because they contain some extra information about the distribution that a simple vector does not. One can access such information using print(x2, details = TRUE):

print(x2, details = TRUE)
#>  [1] 16.531982 10.021074 12.480308 16.165519 11.083118 32.684427 16.661472
#>  [8] 18.085124 10.921481 11.150269 10.673091 12.012880  7.986689  7.500130
#> [15] 10.951995  6.725427 10.789780  5.616512 20.081876  8.138363
#> attr(,"class")
#> [1] "trunc_chisq"
#> attr(,"parameters")
#> attr(,"parameters")$df
#> [1] 14
#> 
#> attr(,"truncation_limits")
#> attr(,"truncation_limits")$a
#> [1] 0
#> 
#> attr(,"truncation_limits")$b
#> [1] Inf
#> 
#> attr(,"continuous")
#> [1] TRUE

Just to be sure that the sample itself matches:

identical(as.vector(x2), x3)
#> [1] TRUE

Speaking of alternative ways to generate the same sample, for the sake of convenience and of users familiar with the sampling functions from the stats package, the wrapper function rtruncchisq() is also available. The results, as you can see below, are identical:

set.seed(2912)
x4 <- rtrunc(1e4, "chisq", df = 14)

set.seed(2912)
x5 <- rtruncchisq(1e4, df = 14)

identical(x4, x5)
#> [1] TRUE

Actually sampling from a truncated distribution

So far, all samples generated are actually not truncated. This is because, by default, the truncation limits a and b are set to the limits of the distribution support, which are 0 and Inf for the chi-squared distribution.

Let us use a simpler distribution for this second example by sampling from Poisson(10):

y1 <- rtruncpois(1e4, 10)
summary(y1)
#>    Min. 1st Qu.  Median    Mean 3rd Qu.    Max. 
#>    0.00    8.00   10.00   10.01   12.00   26.00
var(y1)
#> [1] 10.04213

As expected, the values are all larger than 0 and the mean and variance are 10. If we wanted to generate instead from a Poisson(10) truncated at, say, 8 and 20, we would run:

y2 <- rtruncpois(1e4, 10, a = 9, b = 20)
summary(y2)
#>    Min. 1st Qu.  Median    Mean 3rd Qu.    Max. 
#>    9.00   10.00   11.00   11.63   13.00   20.00
var(y2)
#> [1] 5.159541

Notice how, even with a large sample, the observed mean and variance are still quite far from 10.

Recovering the original parameters

One reliable method of estimating the original lambda used to generate y2 is by running the mlEstimationTruncDist() function:

lambda <- mlEstimationTruncDist(y2, print.iter = TRUE)
#> Estimating parameters for the poisson distribution
#>  it   delta.L2    parameter(s)
#>  1    0.0007325   11.626 
#>  2    0.0005043   11.315 
#>  3    0.0003465   11.064 
#>  4    0.0002378   10.86 
#>  5    0.0001631   10.694 
#>  6    0.0001119   10.558 
#>  7    7.674e-05   10.447 
#>  8    5.264e-05   10.356 
#>  9    3.611e-05   10.281 
#> 10    2.478e-05   10.219 
#> 11      1.7e-05   10.169 
#> 12    1.167e-05   10.127 
#> 13    8.007e-06   10.092
lambda
#>   lambda 
#> 10.06366

More information about that function and how you can tweak it is available on ?mlEstimationTruncDist.